Question:
A telephone wire 120m long and 2.2mm in diameter is stretched by a force of 380N. What is the longitudinal stress? If the length after stretching is 120.10m, what is the longitudinal strain? Determine Young’s modulus for the wire.
Solution:
The cross-sectional area of the wire is……
A = πD² / 4
= π (2.2 x 10^-3 m)² / 4
= 3.8 x 10^-6 m²
Stress = F/A
= 380 N / (3.8 x 10^-6 m²)
= 100 x 10^6 N/m²
= 100 MPa
Strain = ∆l / l
= 0.01 m / 120 m
= 8.3 x 10^-4
Y = stress / strain
= 100 MPa / (8.3 x 10^-4)
= 120,000 Mpa
Question
The density of aluminum is 2.70g/cm³. What volume does 2.0kg occupy?
Solution:
Ρ = m/V or V = m/ρ
= 2000g / 2.70g/cm³
= 741 cm³
Question
The platform is suspended by four wires at its corners. The wires are 3m long and have a diameter of 2.0mm. Young’s modulus for the material of the wires is 180000Mpa. How far will the platform drop (due to elongation of the wires) if a 50kg load is placed at the center of the platform?
Solution:
· ∆L = (3m)(123N) / (3.14x10^-6m²)
= 65x10^-5m
= 0.65mm
Question
Determine the fractional change in volume as the pressure of the pressure of the atmosphere (0.1Mpa) around a metal block is reduced to zero by placing the block in vacuum. The bulk modulus for the metal is 125000 Mpa.
Solution:
B = ∆V / V
= -∆p / B
= - (-0.1) / 125000
= 8x10^-7
Question
Compute the volume change of solid copper cube, 40mm on each edge, when subjected to a pressure of 20 Mpa. The bulk modulus for copper is 125000Mpa.
Solution:
∆V = -V∆p / B
= -(40mm)³(20Mpa) / 125000Mpa
= -10mm³
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